1908 United States presidential election in Vermont

1908 United States presidential election in Vermont
	November 3, 1908
	County Results Taft 60-70% 70-80% 80-90%
President before election; Theodore Roosevelt; Republican	Elected President ; William Howard Taft; Republican

The 1908 United States presidential election in Vermont took place on November 3, 1908 as part of the 1908 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Vermont overwhelmingly voted for the Republican nominees, Secretary of War William Howard Taft of Ohio and his running mate James S. Sherman of New York. They defeated the Democratic nominees, former U.S. Representative William Jennings Bryan and his running mate John W. Kern of Indiana. Taft won the state by a landslide margin of 53.26%.

With 75.08% of the popular vote, Vermont would be Taft’s strongest victory in terms of percentage in the popular vote.

Bryan had previously lost Vermont to William McKinley in both 1896 and 1900.

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