1828 United States presidential election in Vermont

The 1828 United States presidential election in Vermont took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for President and Vice President.

1828 United States presidential election in Vermont

October 31 – December 2, 1828
 
Nominee John Quincy Adams Andrew Jackson
Party National Republican Democratic
Home state Massachusetts Tennessee
Running mate Richard Rush John C. Calhoun
Electoral vote 7 0
Popular vote 25,363 8,350
Percentage 75.23% 24.77%

County Results
Adams
  50-60%
  60-70%
  70-80%
  80-90%

Vermont voted for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. Adams won Vermont by a margin of 50.46%.

With 75.23% of the popular vote, Adam's victory in Vermont was his third strongest state in the 1828 election after Rhode Island and Massachusetts. No Democrat was to win Vermont until Lyndon B. Johnson did so in 1964. This election marks the first time Vermont chose its electors by popular vote rather than appointment by the state legislature.

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.