1880 United States presidential election in Vermont
The 1880 United States presidential election in Vermont took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
County Results
Garfield 60–70% 70–80% 80–90%
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| Elections in Vermont |
|---|
Vermont voted for the Republican nominee, James A. Garfield, over the Democratic nominee, Winfield Scott Hancock. Garfield won Vermont by a margin of 41.66%.
With 69.81% of the popular vote, Vermont would be Garfield's strongest victory in terms of percentage in the popular vote.
The Republican vice presidential nominee Chester Alan Arthur was born in Vermont, more specifically in the town of Fairfield.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.