1876 United States presidential election in Vermont
The 1876 United States presidential election in Vermont took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
County Results
Hayes 50–60% 60–70% 70–80% 80–90%
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| Elections in Vermont |
|---|
Vermont voted for the Republican nominee, Rutherford B. Hayes, over the Democratic nominee, Samuel J. Tilden. Hayes won Vermont by a margin of 36.92%.
With 68.30% of the popular vote, Vermont would be Hayes' strongest victory in terms of percentage in the popular vote.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.