1996 United States presidential election in Alabama

1996 United States presidential election in Alabama
	November 5, 1996
Dole 40–50% 50–60% 60–70% 70–80%	Clinton 40–50% 50–60% 60–70% 70–80% 80–90%
President before election; Bill Clinton; Democratic	Elected President ; Bill Clinton; Democratic

The 1996 United States presidential election in Alabama took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for president and vice president.

Alabama was won by Senator Bob Dole (R-KS), with Dole winning 50.12% to 43.16% over President Bill Clinton (D) by a margin of 6.96%. Billionaire businessman Ross Perot (Reform-TX, although listed as an "Independent" in Alabama) finished in third, with 6.01% of the popular vote.

President Clinton became the first Democrat to carry Montgomery County since Adlai Stevenson II in 1952. As well as the first to win two terms without ever carrying the state. As of the 2020 presidential election, this is the last time a Democrat has carried any of the following counties: Butler, Chambers, Cherokee, Clarke, Coosa, Crenshaw, Etowah, Fayette, Franklin, Marion, Pickens, Walker and Washington.

No subsequent Democratic presidential nominee has been able to match Clinton's 43.16% popular vote share. As of 2020, this remains the last time that Alabama was decided by a single-digit margin.

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