1992 United States presidential election in Oregon

The 1992 United States presidential election in Oregon took place on November 3, 1992, as part of the 1992 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.

1992 United States presidential election in Oregon

November 3, 1992
 
Nominee Bill Clinton George H. W. Bush Ross Perot
Party Democratic Republican Independent
Home state Arkansas Texas Texas
Running mate Al Gore Dan Quayle James Stockdale
Electoral vote 7 0 0
Popular vote 621,314 475,757 354,091
Percentage 42.48% 32.53% 24.21%

County Results

President before election

George H. W. Bush
Republican

Elected President

Bill Clinton
Democratic

Oregon was won by Governor Bill Clinton (D-Arkansas) with 42.48% of the popular vote over incumbent President George H. W. Bush (R-Texas) with 32.53%. Businessman Ross Perot (I-Texas) finished in third, with 24.21% of the popular vote. Clinton ultimately won the national vote, defeating incumbent President Bush.

As of the 2020 presidential election, this is the last time that Curry and Jefferson counties have voted for the Democratic nominee. It was also the first election since 1888 when Crook County had not backed the winning candidate, although Bush’s margin was less than 200 votes and was only a plurality. Nevertheless, this would mark the county becoming a Republican bastion. Deschutes County, which was narrowly won by Clinton via plurality, would not vote for a Democrat again until 2020.

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