1988 United States presidential election in Kansas

The 1988 United States presidential election in Kansas took place on November 8, 1988. All fifty states and the District of Columbia, were part of the 1988 United States presidential election. Voters chose seven electors to the Electoral College, which selected the president and vice president.

1988 United States presidential election in Kansas

November 8, 1988
 
Nominee George H. W. Bush Michael Dukakis
Party Republican Democratic
Home state Texas Massachusetts
Running mate Dan Quayle Lloyd Bentsen
Electoral vote 7 0
Popular vote 554,049 422,636
Percentage 55.79% 42.56%

County Results

President before election

Ronald Reagan
Republican

Elected President

George H. W. Bush
Republican

Kansas was won by incumbent United States Vice President George H. W. Bush of Texas, who was running against Massachusetts Governor Michael Dukakis. Bush ran with Indiana Senator Dan Quayle as Vice President, and Dukakis ran with Texas Senator Lloyd Bentsen.

Kansas weighed in for this election as 2 points more Republican than the national average. The presidential election of 1988 was a very partisan election for Kansas, with over 98 percent of the electorate voting for either the Democratic or Republican parties, and only four political parties appearing on the ballot. Voters from every county in Kansas turned out for the Republican Party, except for three, the largest example being Kansas City's Wyandotte County, which voted primarily Democratic. As of the 2020 presidential election, this is the last time Douglas County voted for a Republican presidential candidate.

Bush won the election in Kansas with a 13-point win, although compared to most previous Republican performances in Kansas this was an underwhelming triumph due to the influence of an ongoing drought and farm crisis.

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.