1940 United States presidential election in Kansas

The 1940 United States presidential election in Kansas took place on November 5, 1940, as part of the 1940 United States presidential election. Voters chose nine representatives, or electors, to the Electoral College, who voted for president and vice president.

1940 United States presidential election in Kansas

November 5, 1940

All 9 Kansas votes to the Electoral College
 
Nominee Wendell Willkie Franklin D. Roosevelt
Party Republican Democratic
Home state New York New York
Running mate Charles L. McNary Henry A. Wallace
Electoral vote 9 0
Popular vote 489,169 364,725
Percentage 56.86% 42.40%

County Results

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

Kansas was won by Wendell Willkie (R–New York), running with Minority Leader Charles L. McNary, with 56.86 percent of the popular vote, against incumbent President Franklin D. Roosevelt (D–New York), running with Secretary Henry A. Wallace, with 42.40 percent of the popular vote. This was the first time since 1896 that Kansas voted for a losing candidate, and the first time since 1884 that the state backed a losing Republican in a presidential election.

With 56.86 percent of the popular vote, Kansas would prove to be Willkie's third strongest state in the 1940 election in terms of popular vote percentage after South Dakota and neighboring Nebraska.

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