1840 United States presidential election in Indiana

The 1840 United States presidential election in Indiana took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

1840 United States presidential election in Indiana

October 30 - December 2, 1840
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 9 0
Popular vote 65,302/65,280 51,604/51,696
Percentage 55.86%/55.79 44.14%/44.18%

County Results

President before election

Martin Van Buren
Democratic

Elected President

William Henry Harrison
Whig

Indiana voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Indiana by a margin of 11.72%./11.61%

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