1836 United States presidential election in Indiana

The 1836 United States presidential election in Indiana took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

1836 United States presidential election in Indiana

November 3 – December 7, 1836
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate Francis Granger Richard Johnson
Electoral vote 9 0
Popular vote 41,281/41,339 32,478/33,084
Percentage 55.97%/55.55% 44.03%/44.45

Indiana voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Indiana by a margin of 11.94%./11.10%

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