1996 United States presidential election in Idaho

The 1996 United States presidential election in Idaho took place on November 5, 1996, as part of the 1996 United States presidential election. State voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

1996 United States presidential election in Idaho

November 5, 1996
 
Nominee Bob Dole Bill Clinton Ross Perot
Party Republican Democratic Reform
Home state Kansas Arkansas Texas
Running mate Jack Kemp Al Gore Patrick Choate
Electoral vote 4 0 0
Popular vote 256,595 165,443 62,518
Percentage 52.18% 33.65% 12.71%

County Results

President before election

Bill Clinton
Democratic

Elected President

Bill Clinton
Democratic

Idaho was won by Senator Bob Dole (R-KS) over President Bill Clinton (D), with Dole winning 52.18% to 33.65% for a margin of 18.53%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third, with 12.71% of the popular vote. As of the 2020 presidential election, this is the last election in which Nez Perce County and Shoshone County voted for a Democratic presidential candidate. Clinton became the first ever Democrat to win the White House without carrying Benewah or Lewis Counties, and the first to do so without carrying Clearwater County since Woodrow Wilson in 1916.

With 52.18% of the popular vote, Idaho proved to be Dole's fourth strongest state in the 1996 election after neighboring Utah, Kansas and Nebraska. The state also proved to be Ross Perot's third strongest state in the election after Maine and neighboring Montana. This also marked the first time since statehood that a Democrat was reelected president without carrying Idaho.

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