1948 United States presidential election in Nebraska
The 1948 United States presidential election in Nebraska took place on November 2, 1948, as part of the 1948 United States presidential election. Voters chose six representatives, or electors, to the Electoral College, who voted for president and vice president.
| ||||||||||||||||||||||||||
All 6 Nebraska votes to the Electoral College | ||||||||||||||||||||||||||
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
| ||||||||||||||||||||||||||
County Results
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| Elections in Nebraska |
|---|
| Government |
Nebraska was won by Governor Thomas Dewey (R–New York), running with Governor Earl Warren, with 54.15% of the popular vote, against incumbent President Harry S. Truman (D–Missouri), running with Senator Alben W. Barkley, with 45.85% of the popular vote. As of the 2020 presidential election, this is the last occasion Wheeler County has voted for a Democratic presidential candidate.
Dewey won Nebraska by an 8.3% margin, a significantly reduced margin from his 1944 run, when he won by 17.2%.
Though he failed to win the state, Truman's performance in Nebraska was the best for a Democrat since Franklin Roosevelt's victory in 1936, and would remain the best until Lyndon B. Johnson's narrow victory in 1964. This was the only election between 1900 and 1992 in which Nebraska voted differently than neighboring Colorado.
With 54.15% of the popular vote, Nebraska would prove to be Dewey's third strongest state in the nation after Vermont and Maine.