1900 United States presidential election in Iowa

The 1900 United States presidential election in Iowa took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Voters chose 13 electors to the Electoral College, which selected the president and vice president.

1900 United States presidential election in Iowa

November 6, 1900
 
Nominee William McKinley William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Theodore Roosevelt Adlai Stevenson I
Electoral vote 13 0
Popular vote 307,808 209,265
Percentage 58.04% 39.46%

County Results

President before election

William McKinley
Republican

Elected President

William McKinley
Republican

Iowa was won by the Republican incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York. They defeated the Democratic nominees, former U.S. Representative and 1896 Democratic presidential nominee William Jennings Bryan and his running mate, former Vice President Adlai Stevenson I. McKinley won the state by a margin of 18.58% in this rematch of the 1896 presidential election. The return of economic prosperity and recent victory in the Spanish–American War helped McKinley to score a decisive victory.

Bryan had previous lost Iowa to McKinley four years earlier and would later lose the state again in 1908 to William Howard Taft.

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.