1860 United States presidential election in Maryland

The 1860 United States presidential election in Maryland took place on November 6, 1860, as part of the 1860 United States presidential election. Maryland voters chose eight representatives, or electors, to the Electoral College, who voted for president and vice president.

1860 United States presidential election in Maryland

November 6, 1860
 
Nominee John Breckenridge John Bell Stephen A. Douglas
Party Southern Democratic Constitutional Union Democratic
Home state Kentucky Tennessee Illinois
Running mate Joseph Lane Edward Everett Herschel V. Johnson
Electoral vote 8 0 0
Popular vote 42,482 41,760 5,966
Percentage 45.93% 45.14% 6.45%

County Results

President before election

James Buchanan
Democratic

Elected President

Abraham Lincoln
Republican

Maryland was won by the Southern Democratic candidate 14th Vice President of the United States John C. Breckinridge of Kentucky and his running mate Senator Joseph Lane of Oregon. They defeated the Constitutional Union candidate Senator John Bell of Tennessee and his running mate the 15th Governor of Massachusetts Edward Everett as well as Democratic candidate Senator Stephen A. Douglas of Illinois and his running mate 41st Governor of Georgia Herschel V. Johnson. Breckinridge won the state by a narrow margin of 0.79%.

Despite coming in a distant fourth place with 2,294 votes Abraham Lincoln did receive over 2,000 more votes than John C. Frémont received in 1856 and would later win the state in 1864 with 55% of the vote.

This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.