1992 United States House of Representatives elections
The 1992 United States House of Representatives elections were held on November 3, 1992, to elect U.S. Representatives to serve in the 103rd United States Congress. They coincided with the 1992 presidential election, in which Democrat Bill Clinton was elected as President, defeating Republican incumbent President George H. W. Bush.
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All 435 seats in the United States House of Representatives 218 seats needed for a majority | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
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Results: Democratic hold Democratic gain Republican hold Republican gain Independent hold | |||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
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Despite this, however, the Democrats lost a net of nine seats in the House to the Republicans, in part due to redistricting following the 1990 census. This election was the first to use districts drawn up during the 1990 United States redistricting cycle on the basis of the 1990 census. The redrawn districts were notable for the increase in majority-minority districts, drawn as mandated by the Voting Rights Act. The 1980 census resulted in 17 majority-black districts and 10 majority-Hispanic districts, but 32 and 19 such districts, respectively, were drawn after 1990.
This was the first time ever that the victorious presidential party lost seats in the House in two consecutive elections. As of 2022, this is the last congressional election in which Republicans won a House seat in Rhode Island, and the last time the Democrats won the House for more than two consecutive elections.