Hobart Township, Lake County, Indiana
Hobart Township is one of eleven townships in Lake County, Indiana. As of the 2010 census, its population was 39,417 and it contained 16,366 housing units.
| Census | Pop. | Note | %± |
|---|---|---|---|
| 1890 | 2,197 | — | |
| 1900 | 2,718 | 23.7% | |
| 1910 | 3,729 | 37.2% | |
| 1920 | 5,621 | 50.7% | |
| 1930 | 9,135 | 62.5% | |
| 1940 | 12,472 | 36.5% | |
| 1950 | 21,871 | 75.4% | |
| 1960 | 39,223 | 79.3% | |
| 1970 | 40,825 | 4.1% | |
| 1980 | 42,548 | 4.2% | |
| 1990 | 38,942 | −8.5% | |
| 2000 | 39,636 | 1.8% | |
| 2010 | 39,417 | −0.6% | |
| 2020 | 40,652 | 3.1% | |
| Source: US Decennial Census | |||
Hobart Township | |
|---|---|
Township | |
| Coordinates: 41°32′48″N 87°15′53″W | |
| Country | United States |
| State | Indiana |
| County | Lake |
| Government | |
| • Type | Indiana township |
| Area | |
| • Total | 25.98 sq mi (67.3 km2) |
| • Land | 25.47 sq mi (66.0 km2) |
| • Water | 0.51 sq mi (1.3 km2) |
| Elevation | 627 ft (191 m) |
| Population (2020) | |
| • Total | 40,652 |
| • Density | 1,547.4/sq mi (597.5/km2) |
| FIPS code | 18-34132 |
| GNIS feature ID | 453414 |
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