1990 PGA Championship
The 1990 PGA Championship was the 72nd PGA Championship, held August 9–12 at Shoal Creek Golf and Country Club in Birmingham, Alabama. Wayne Grady won his only major championship, three strokes ahead of runner-up Fred Couples.
| Tournament information | |
|---|---|
| Dates | August 9–12, 1990 |
| Location | Birmingham, Alabama 33.438°N 86.612°W |
| Course(s) | Shoal Creek Golf and Country Club |
| Organized by | PGA of America |
| Tour(s) | PGA Tour |
| Statistics | |
| Par | 72 |
| Length | 7,145 yards (6,533 m) |
| Field | 152 players, 74 after cut |
| Cut | 151 (+7) |
| Prize fund | $1.35 million |
| Winner's share | $225,000 |
| Champion | |
| Wayne Grady | |
| 282 (−6) | |
| Location map | |
Location in the United States Location in Alabama | |
In the final round, Couples led by a stroke after a birdie at the 12th hole, but then had four consecutive bogeys, while Grady shot par for the rest of the round. Defending champion Payne Stewart was in the final pairing with Grady, but was two-over par on the front nine. On the par-5 11th hole, he put his third shot into the water and fell from contention with a triple bogey.
Grady became the third Australian-born player to win the PGA Championship, preceded by Jim Ferrier in 1947 and David Graham in 1979. It was Grady's second and final win on the PGA Tour.
Concerns about racial discrimination in the club's membership caused many sponsors to pull their network television advertising, including IBM. This was the final year that ABC carried the broadcast, replaced by CBS in 1991.