1989–90 FIRA Trophy
The 1989–90 FIRA Trophy was the 28th edition of a European rugby union championship for national teams. The format returned to a one-year tournament, with each team facing each other only once.
| 1989-90 FIRA Trophy | |||
|---|---|---|---|
| Date | 22 October 1989 – 27 May 1990 | ||
| Countries | France Italy Romania Poland Soviet Union | ||
| Tournament statistics | |||
| Champions | France Soviet Union Romania | ||
| Matches played | 10 | ||
| |||
The tournament was won by France, Romania and Soviet Union, who all finished with three wins and one loss, and the same points. France only awarded caps in their 12-6 loss at home to Romania. Italy finished in a disappointing 4th place, with a single win, while Poland lost all their four games and was relegated. Their best result was a 25-19 loss to Romania abroad, in a game where the Romanians didn't awarded caps.
Portugal and Spain where the winners of the Second division groups, facing each other's in a final, won by the Spaniards (29-6).
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.