1889 United States House of Representatives elections
There were 14 elections to the United States House of Representatives in 1889 to the 50th United States Congress and 51st United States Congress. Of these, at least 10 were special elections and 4 were general elections for new states.
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15 (out of 336) seats to the United States House of Representatives 169 seats needed for a majority | ||||||||||||||||||||||
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One of the elections was for two seats, so the total members elected were 15.
The only gains came from new seats, created for the new states of Montana, South Dakota, North Dakota, and Washington. From these new states, 5 new Republicans were elected to the House.
Elections are listed by date and district.
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